(2)x=Y-4
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(x - 5)(x + 4)
It is either 2|x| - 3 or 2|x-3| depending on if the minus three is part of the absolute value.
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
The value of -3 is -3. The value of x has no bearing on that!
You need to know the value of either x or y. After that it's 6-year old arithmentic.