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Solve the following system of equations express your answer as an ordered pair 2x plus 5y equals 16 and -5x minus 2y equals 2?
The solutions are: x = -2 and y = 4
What is the solution of x equals 6y-4 and x equals -2y plus 28 using substitution?
x=6y-4x=-2y+28Substitute (6y-4) for x in the second equation and solve for y:6y-4=-2y+288y=32y=4Then solve for x:x=6(4)-4=20(20,4)
Solve the following system of equations x plus 2y -6 equals z 3y-2z equals 7 4 plus 3x equals 2y -5z?
x+2y-6=z -z -z x+2y-z-6=0 +6 +6 ---------> x+2y-z=6 3y-2z=7 ---------> 0x+3y-2z=7 4+3x=2y-5z -3x -3x ---------> -3x+2y-5z=4 Put them into a matrix, for x,y,z and their answers. Solve for [A]-1[B], and the answer comes to: x= 1.75, y= 1.5, and z= -1.25
Can anyone solve x plus 2y equals 8 and 3x-2y equals 8 as a simultaneous equation and show their working?
x+2y=8 Here you must add the expressions (2y - 2y = 0) 3x-2y=8 4x=16 Now you are left with a multiple of x so you can simply divide by 4 x=4 on both sides of the = 4+2y=8 Now you substitute x=4 into one of the original equations to find y 2y=4 y=2 Hope this helped.
How do you graph the equation x plus 2y equals 4?
First, write out the problem: x+2y=4 then you have to simplify it so that only y is on one side x+2y=4 -4 -4 x+2y-4=0 -2y -2y x-4=-2y / -2 = -1/2x + 2 = y then, draw out a graph: and, let's say, x=4, then you plug that into the equation, and solve for y in this case, if x=4, then y=0, so one of the points would be (4, 0)
