A cylinder with a diameter of 7 meters and a height of 12 meters has a volume of 461.81 cubic meters.
The volume is 461.81 cubic meters.
1m = 100cm, therefore 12m = 1200cm. 12m is > 120 cm
18m-7+12m
12m + 3n - 6m + 7n6m + 10n
12m + 2n - 3m + 11n = 9m + 13n
The volume is 461.81 cubic meters.
The cylinder's diameter will be about 32.58m
339.29 m3 to two decimal places.
3.14 * 3.52 *12= 461.58m3Volume=pi * r^2 * hr=.5d 7 * .5 = 3.5h=12
using the volume formula for a cylinder, V = 2*pi*R*H, the volume of a cylinder with R=4 and H=5 is 125.66 sq. in. The formula for a cylinder is V = Pi*R²*H where Pi = 3.1416 and R² = Radius multiplied by itself. Using the formula: V = Pi*R²*H V = 3.1416 * (4*4) * 5 V = 3.1416*16*5 V = 251.328 cu in
I presume the tunnel has an arch shaped cross-section with a semicircle on top of a rectangle. In this case the volume of the tunnel is the volume of the cuboid bottom plus the volume of half cylinder which forms the top. The volume of the half cylindrical top is ½πr²h = ½ × π × (6m)² × 25m = 450π m³ The volume of the cuboid is length × width × height. The length is 25m. The width is the diameter of the top half cylinder which is twice the radius at 2 x 6m = 12 m. The height is not clear. I am going to presume it is to the top of the arch, so that the height of the cuboid is the height less the radius of the cylinder, namely 7m - 6m = 1m. Thus the volume of the cuboid bit is 25m x 12m x 1m = 300 m³ Thus the volume of the tunnel as a whole is 300 m³ + 450π m³ ≈ 1713.72 m³ (If the 7m height refers to the height of the vertical walls, then the volume of the cuboid is 25m x 12m x 7m = 2100 m³ and the volume of the tunnel is 2100 m³ + 450π m³ ≈ 3513.72 m³.)
What is the volume of an m and m
120m2
The volume of the tank can be calculated using the formula for the volume of a cylinder: V = πr^2h where r is the radius (half of the diameter). Given the diameter is 20 meters, the radius is 10 meters. Substituting the values, V = π(10)^2 * 12 = 3769.91 cubic meters.
To find the volume needed, you can use the formula: M1V1 = M2V2. Here, M1 = 12M (initial concentration), V1 = volume of 12M HCl solution needed, M2 = 0.100M (final concentration), and V2 = 250 mL. Rearranging the formula, V1 = (M2 * V2) / M1 = (0.100M * 250mL) / 12M = 2.08 mL. Therefore, you will need 2.08 mL of the 12M HCl solution to prepare 250 mL of 0.100M solution.
The formula for finding the volume of a cylinder is pi multiplied by radius squared multiplied by the height. So for this case it would be pi multiplied by 6 squared multiplied by 7.5. But since you want it when it is HALF full, you would divide by two, so the answer would be 135 multiplied by pi, or around 424 metres squared of water.
Area of traingle = Base * Height / 2 = 18*12/2 = 108 m2