Any point on the graph can be the center of a circle. If the center is on the x-axis, then the circle is symmetric with respect to the x-axis.
No, but they are symmetric with respect to a line parallel to the y-axis - which could be the y-axis itself.
When you with respect to the x-axis then this is like saying with reference to the x-axis. You are using the x-axis as a guide.
All y-values in the function are multiplied by -1. This function is 'flipped' over the x-axis.
An x-intercept is the point where a function intersects the x-axis on a Cartesian coordinate plane. For example, if the graph of a parabola is plotted and the graph intersects the x-axis on the coordinate plane, the point(s) where the graph intersects the x-axis are the x-intercepts for that function.
x=y²
Any point on the graph can be the center of a circle. If the center is on the x-axis, then the circle is symmetric with respect to the x-axis.
A function that is symmetric with respect to the y-axis is an even function.A function f is an even function if f(-x) = f(x) for all x in the domain of f. that is that the right side of the equation does not change if x is replaced with -x. For example,f(x) = x^2f(-x) = (-x)^2 = x^2
No, but they are symmetric with respect to a line parallel to the y-axis - which could be the y-axis itself.
f(x) = 0 is a constant function. This particular constant function is both even and odd. Requirements for an even function: f(x) = f(-x) Geometrically, the graph of an even function is symmetric with respect to the y-axis The graph of a constant function is a horizontal line and will be symmetric with respect to the y-axis. y=0 or f(x)=0 is a constant function which is symmetric with respect to the y-axis. Requirements for an odd function: -f(x) = f(-x) Geometrically, it is symmetric about the origin. While the constant function f(x)=0 is symmetric about the origin, constant function such as y=1 is not. and if we look at -f(x)=f(-x) for 1, we have -f(x)=-1 but f(-1)=1 since it is a constant function so y=1 is a constant function but not odd. So f(x)=c is odd if and only iff c=0 f(x)=0 is the only function which is both even and odd.
symmetric about the y-axis symmetric about the x-axis symmetric about the line y=x symmetric about the line y+x=0
If the function, or channel, or whatever you are reffering to has a axis of symmetry across both the y-axis and the x-axis
An even function is symmetric about the y-axis. The graph to the left of the y-axis can be reflected onto the graph to the right. An odd function is anti-symmetric about the origin. The graph to the left of the y-axis must be reflected in the y-axis as well as in the x-axis (either one can be done first).
When you with respect to the x-axis then this is like saying with reference to the x-axis. You are using the x-axis as a guide.
If a function is even ie if f(-x) = f(x). Such a function would be symmetric about the y-axis. So f(x) is a many-to-one function. The inverse mapping then is one-to-many which is not a function. In fact, the function need not be symmetric about the y-axis. Symmetry about x=k (for any constant k) would also do. Also, leaving aside the question of symmetry, the existence of an inverse depends on the domain over which the original function is defined. Thus, y = f(x) = x2 does not have an inverse if f is defined from the real numbers (R) to R. But if it is defined from (and to) the non-negative Reals there is an inverse - the square-root function.
)the answer is the left end of the graph of the function goes up and the right goes down, 2)it has 5 zeros and at most 4 relative maximums and minimums, 3)and it is a reflection and a translation to the left of the parent function.
The points (-7, 1) and (-7, -1) are symmetric about the x-axis.