Oh, dude, a rectangle with a perimeter of 18 could have sides measuring 4.5, 4.5, 4.5, and 4.5. So, like, each side would be 4.5 units long, and when you add them all up, you get a perimeter of 18 units. It's like basic math, man.
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A rectangle with a perimeter of 18 units can have various dimensions, but the sum of its four sides must equal 18 units. If we denote the length of the rectangle as L and the width as W, the formula for the perimeter of a rectangle is 2(L + W). Given the perimeter of 18, we can set up the equation 2(L + W) = 18. Additional constraints or information would be needed to determine the specific dimensions of the rectangle.
There are an infinite number of possible solutions. A rectangle with length L and width is 9-L, for any L between 4.5 and 9 will satisfy the requirements.
Examples: 4.6 x 4.4 or 4.7 x 4.3 or 4.71 x 4.29 etc.
A rectangle with sides
Let L be the length of the rectangle and W the width, then L = 2W - 3. The perimeter = 2L + 2W = 2(2W - 3) + 2W = 6W - 6 But the perimeter measures 18"so, 6W - 6 = 18 : 6W = 24 : W = 4 The width of the rectangle is 4".
7 feet 2(7+2) = 18 feet 7*2 = 14 square feet
The perimeter of a rectangle is not sufficient to determine its length.
Draw it with dimensions of (6 cm) by (3 cm).
Length + width = half of perimeter, ie 18 cm. 18 - 4 = 14, 14/2 = 7 so sides are 7 and 11 cm and area = 77sq cm