write an algorithm to find the roots of a quadratic equation
It too will have a value of 5
How you solve an equation that doesn't factor is to plug a quadratic equation's format; ax2+bx+c into the quadratic formula which is x=-b+square root to (b2-4ac)/2a.
The answer to the question, as stated, is that the other root could be anything. However, if all the coefficients of the quadratic equation are real numbers, then the other root is 1 minus 3i.
It is the equation inside the square root of the Quadratic FormulaIf > 0 there is a solutionIf < 0 there is no solutionBecause you can not calculate the Square Root of a Negative Number
Using the quadratic equation formula: x = -5-/+ the square root of 7
The graph of a quadratic equation is called a parabola.The graph of a quadratic equation is called a parabola.The graph of a quadratic equation is called a parabola.The graph of a quadratic equation is called a parabola.
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
The roots are (if the equation is of the form Ax2 + Bx + C = 0 ((-B) + Square Root of (B2 - 4xAxC)) / 2xA and ((-B) - Square Root of (B2 - 4xAxC)) / 2xA
the graph for a quadratic equation ct5r