The answer to the question, as stated, is that the other root could be anything.
However, if all the coefficients of the quadratic equation are real numbers, then the other root is 1 minus 3i.
-7 therefore the quadratic equation has no real roots
It has no roots because the discriminant of the given quadratic equation is less than zero.
If the discriminant of a quadratic equal is zero then it will have two equal roots.
Using the quadratic equation formula:- x = -4.706950048 and x = 0.849071913
x = 2 and x = 4
The roots are: x = -5 and x = -9
-7 therefore the quadratic equation has no real roots
This quadratic equation has no real roots because its discriminant is less than zero.
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
If you mean b^2 -4ac then it is the discriminant of a quadratic equation. If the discriminant equals 0 then the equation has 2 equal roots. If the discriminant is greater than 0 then the equation has 2 different roots. If the discriminant is less than 0 then it has no real roots.
If it was expressed as a quadratic equation it would have no roots because the discriminant is less than zero
It has no roots because the discriminant of the given quadratic equation is less than zero.
If the discriminant of a quadratic equal is zero then it will have two equal roots.
Using the quadratic equation formula:- x = -4.706950048 and x = 0.849071913
x = 2 and x = 4
There are no integer roots of this equation. Using the quadratic formula gives roots of 1.34 and 3.04 plus or minus loose change in each case.
Using the discriminant formula for a quadratic equation k has a value of 8/25 or maybe 0.