To find the equation of the line perpendicular to (y - 4x + 2 = 0), we first determine the slope of the given line, which is 4. The slope of the line perpendicular to it will be the negative reciprocal, (-\frac{1}{4}). Using the point (4, 4) and the point-slope form of the equation (y - y_1 = m(x - x_1)), we have:
[ y - 4 = -\frac{1}{4}(x - 4). ]
This simplifies to (y = -\frac{1}{4}x + 5).
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
To determine the equation of a line that is perpendicular to another line and passes through the point (6, 2), we first need the slope of the original line. If the slope of the original line is ( m ), the slope of the perpendicular line will be ( -\frac{1}{m} ). Without the specific line's equation, we can't compute the exact perpendicular line. However, if you have options like A, B, etc., you can find the correct one by substituting the point (6, 2) into each equation to see which one satisfies it.
2-3
Yes, I could, if I knew the slope of the line given.
The x-coordinate of any point on the y-axis is 0. The y-axis is a line perpendicular to the x-axis. Any point on a line perpendicular to the x-axis has the same x-coordinate. The y-axis is the line perpendicular to the x-axis through 0, and has the equation x = 0; similarly, the x-axis is the line perpendicular to the y-axis through 0 and has the equation y = 0.
That would depend on its slope which has not been given.
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
General formula
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
2-3
The perpendicular postulate states that if there is a line, as well as a point that is not on the line, then there is exactly one line through the point that is perpendicular to the given line.
Yes, I could, if I knew the slope of the line given.
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
The x-coordinate of any point on the y-axis is 0. The y-axis is a line perpendicular to the x-axis. Any point on a line perpendicular to the x-axis has the same x-coordinate. The y-axis is the line perpendicular to the x-axis through 0, and has the equation x = 0; similarly, the x-axis is the line perpendicular to the y-axis through 0 and has the equation y = 0.
Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4
If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13