It is: y-4 = 9(x-5) => y = 9x-41
Or as: 9x-y-41 = 0.
Another version of the standard form of a linear equation in coordinates x and y is y = s x + k, where s is the slope and k is a constant. In this question, the slope s is directly given, as is the value of y at the point where x = 5 so that- 44. The slope is always the coefficient of x in this standard form, and the constant k can be determined by solving the equation for the coordinates of the given point: When x = 5, y = (9 X 5) + k, and y(5) is stated by the question to be 4. 9 X 5 equals 45; therefore to obtain the right value for k, 45 + k =4 or k = - 41.
The standard form of the equation is therefore y = 5x - 41.
If the slope is undefined, it is a vertical line. Therefore the equation is x=2.
If you mean a point of (-1, 4) and a slope of -3 then the equation is y = -3x+1
If you mean passing through (1, 2) with a slope of -3 then it is y = -3x+5
y = 1/3x+4/3
Using the standard form y = mx + c Where m = slope of '2' The point ( 5,-6) is displaced against ( x,y) Hence y - - 6 = 2(x - 5) Note the 'double' negative. y + 6 = 2x - 10 y = 2x - 16
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
If the slope is undefined, it is a vertical line. Therefore the equation is x=2.
If you mean a point of (-1, 4) and a slope of -3 then the equation is y = -3x+1
what
It is the equation of a line passing through the point (0, 1/3) and with slope 4/3
If you mean passing through (1, 2) with a slope of -3 then it is y = -3x+5
It is: y = 5x+6
The standard form is: 5x - y + 4 = 0
y = 1/3x+4/3
If you mean a point of (0, 3) and a slope of 2 then the equation is y = 2x+3
Using the standard form y = mx + c Where m = slope of '2' The point ( 5,-6) is displaced against ( x,y) Hence y - - 6 = 2(x - 5) Note the 'double' negative. y + 6 = 2x - 10 y = 2x - 16