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The equation for the axis of symmetry is?
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
What is an equation of the axis of symmetry of the parabola represented by y equals -x2 plus 6x-4?
Line of symmetry: x = 3
What are the vertex and the axis of symmetry of the equation y equals 2x² plus 4x - 10?
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
Why is the axis of symmetry halfway between two points on the parabola that have the same y-value?
The axis of symmetry is a line where if you were to fold the graph in half on that line, every point should perfectly match up with it's opposite.
Which equation represents the axis of symmetry of the graph of the equation y equals x2-6x 5?
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
