c= sq rt of 73
Assuming the decimals go to inifinity.; it should be written as -0.3333.... ( Note the periods. This inidicates to mathemticians that it recurs to infinity). -0.333.... = -1/3 Method Let P = -0.3333.... 10P = -3.33333... Subtract 9P = -3 Note the recurring decimals subtract to zero. P = -3/9 P = -1/3
3 squared is 9, 5 squared is 25. So the product is 225.
3 squared is 3 x 3 or 9.
n^3 mean a number Squared by 3
x^2-8x+3 This expression cannot be factored as (x+a)(x+b) where a and b are integers. This is because you cannot find two integers such that their sum is -8 and product 3.
* a2 + b2 = c2 * a = 3 * b = 8 * (3)2 + (8)2 = c2 * 9 + 64 = c2 * 73 = c2 * c = √73
Assuming that decimals and fractions can be used, .1, .2, .3, .4, and .5. If they cannot be used, then the question has no solution.
Assuming the thing is as written and there are no brackets missed out then it is just 4 squared times 3 = 16x3=48.
0.03 = 3%If you want to convert from decimals to percentages, then you just need to multiply the whole decimal by 100%. If you want to convert from percentages to decimals, you just divide by 100%.I'm assuming you mean .003, which in that case, 3%.
Irrational numbers are real numbers which cannot be expressed as fractions. In other words, decimals that never repeat. Examples: sqrt(2) -pi 4*sqrt(3)
3/8 is in its simplest form.
3 squared=9 3 squared=3*3 3*3=9
No, an integer cannot contain a decimal place. Instead consider using a double or a float for decimals.
3 squared = 9 4 squared = 16 9 x 16 = 144 3 squared x 4 squared = 144
3 - 3 squared = 6 * * * * * NO! 3 - 3 squared = 3 - 9 = -6
-3 squared by 2
900 = 9 x 100 9 can be written as 3 to the power of 2 100 can be written as 10 to the power of 2 It is then written as (3 squared) x (10 squared) I cannot with the editor we use show how to write 3 squared or 10 squared but I hope you know ( 3 superscript 2) x (10 superscript 2).