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x^2-8x+3
This expression cannot be factored as (x+a)(x+b) where a and b are integers.
This is because you cannot find two integers such that their sum is -8 and product 3.
(4x + 1)(2x + 3)
(4x - 3)(2x + 3)
-8x + 3x2 - 3
x - 3
4x+8x+3 = 12x+3
2(4x - 3)(x + 3)
2(x + 3)(x + 1)
The answer is (2x^2+3)(4x+1)
(x - 5)(x - 3)
(8x - 3)(8x + 3)
(x-3)(x-5) = 0
x + 3
x + 5
(x-3)(3x+1)