Algebraically it is written as ' n^(2) - n'. This factors to ' n(n-1)'.
(n*n)+n
If you mean: (x+3) squared = (x+2) squared +11 Then the value of x works out as 3
The statement n3 is ambiguous. I presume you mean n3, which means n cubed or n to the power of 3 (n*n*n). However, n3 (which should really be written as 3n) means n times 3 (n*3).
3 squared is 9, 5 squared is 25. So the product is 225.
It means N times N. 3 squared is 9.
Simple equation lad. In your example, you said n=4 and x= n squared + n - 1 + (n-2)squared + (n-3)squared. You simply write n²+n-1+(n-2)²+(n-3)² I hope that is what you mean by what you say. P.S. To get the to the power of sign, hold alt and press 0178 for ², and 0179 for ³
If that's n squared, the multiples are n squared, 2 n squared, 3 n squared and so on. If that's n + 2, the multiples are n + 2, 2n + 4, 3n + 6 and so on.
3 squared is 9 and so 9n = 63 which means n = 7
are you sure you don't mean "4n squared - 26n + 42" ?? This would give 2(2n-7)(n-3) Davehx
Take any positive integer n. If you square it, and subtract 1, you get (x squared - 1). If you take (n - 1) and (n + 1), and multiply them together, you get n squared - n + n - 1, which is the same as (n squared - 1).
n squared x n n x n x n = n cubed n x n = n squared n squared x n = n cubed
If you mean n squared+11n+18 then it is (n+2)(n+9) when factored
2 squared divided by 3 squared ie 4/9 in general, (a/b)^n = a^n/b^n . In this case (2/3)^2=2^2/3^2=4/9 Check: 2/3 = .667 squared = 0.444889; 4/9 =0.44444. Near enough!
Oh, dude, adding n squared plus n squared is like adding apples to apples, you know? It's just like, you take two n squared terms and you add them together to get 2n squared. It's not rocket science, man. Just double up those n squares and you're good to go.
It is 2n^3 + 7n^2 - 13n + 3
Algebraically it is written as ' n^(2) - n'. This factors to ' n(n-1)'.