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(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4
(multiply x2 - 3 by x, and subtract the product from the dividend)
1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x
2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12
(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)
1. 4x(x - 3) = 4x2 - 12 = 4x2 - 12
2. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
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What is the inverse of x3 plus 1?
The inverse of a number is 1 divided by that number. So the inverse of x3 + 1 is 1/(x3 + 1).
When x3 plus 3x2 2x plus 7 is divided by x plus 1 the remainder is?
That depends on whether or not 2x is a plus or a minus
What is the quotient and remainder if any when the expession 4x4 -x3 plus 17x2 plus 11x plus 4 is divided by 4x plus 3?
Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7
What is the factor of x3 plus x2 plus 4x plus 4?
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
What is x plus 4 divided by x3 -11x plus 20?
(x + 4) / (x3 - 11x + 20) = (x + 4) / (x2 + 4x - 5)(x + 4) = 1 / (x2 + 4x - 5) = 1 / (x + 5)(x - 1), where x ≠ -4
