(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4
(multiply x2 - 3 by x, and subtract the product from the dividend)
1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x
2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12
(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)
1. 4x(x - 3) = 4x2 - 12 = 4x2 - 12
2. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
The inverse of a number is 1 divided by that number. So the inverse of x3 + 1 is 1/(x3 + 1).
Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7
That depends on whether or not 2x is a plus or a minus
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
(x + 4) / (x3 - 11x + 20) = (x + 4) / (x2 + 4x - 5)(x + 4) = 1 / (x2 + 4x - 5) = 1 / (x + 5)(x - 1), where x ≠ -4
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
4
(-x3 + 75x - 250) / (x + 10) = x2 - 10x - 25
The inverse of a number is 1 divided by that number. So the inverse of x3 + 1 is 1/(x3 + 1).
2x2+7/x1
Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7
That depends on whether or not 2x is a plus or a minus
1.6667
x3 /12 + 16x + c
x3+3x2+3x+2 divided by x+2 equals x2+x+1
== == Suppose f(x) = x3 + 3x2 - 2x + 7 divisor is x + 1 = x - (-1); so rem = f(-1) = 11
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7