3q + 2p
-2p squared
The difference of p and q can be written : p - q Twice the difference is therefore 2 x (p - q) which can also be written as 2(p - q) OR 2p - 2q. Consequently you can create another variable (say) y and make this equal to twice the difference of p and q by simply writing, y = 2(p -q)
5p-1=2p-20 3p=21 p=7
P! / q!(p-q)!
If: 2p+5r = q Then: p = (q-5r)/2
3q + 2p
p=3 !
28
p + 22q2
It equals 2p because p+p=2p.
Solving by elimination: p = 3 and q = -2
It is 2p + 3q. This is an expression and so cannot be solved. It cannot be simplified, and without information about the values of p and q, it cannot be evaluated.
4t - 2p
5p-7q
6
6