The new volume is 76.566 cubic inches.
Fist you've got to find the volume of the sphere, if the radius was 4cm then it would be...4/3*pi*r3=268cm V of cylinder= pi*r2*l (the radius for example is 8cm) 268=pi*64*l L=268/64pi =1.3cm
Area = 4*pi*42 = 64pi square units
To find the surface area of a sphere, the formula is: 4pi*r2So plug in numbers: 4pi(4)24pi(16)=64pi
Surface area of the sphere: 4*pi*42 = 201.062 square inches rounded to 3 decimal places
Area = 64pi implies that radius = 8 units So diameter = 2*rad = 16 units.
64pi (miles square)
64pi
If by ' A 64 pi' you mean the Area. Then A = 64pi Since A = pi r^2 and 64 is 8^2 Then we can say r(radius)= 8 The circumference of a circle is C = 2pir Hence C = 2 x 3.14 x 8 C = 16 x 3.14 C = 50.24 linear units. The value for 'pi' at 3.14 is an approximation.
A = 64pi
From your question, we can't tell whether [ 64 pi ] is the area of the circleor the sector.The area of a circle is [ pi R2 ].If [ 64 pi ] is the area of the circle, then the radius is [ 8 ], and we don't careabout the sector.If [ 64 pi ] is the area of the sector, then the area of the full circle is [ 256 pi ](because the 90-degree sector is 1/4 of the circle), and the radius is [ 16 ].
The area of a cross section of a cylinder that is parallel to its base is equal to the area of the base. In this case, the base of the cylinder is a circle with a radius of 8 inches. Therefore, the area of the cross section is 64pi square inches.
The answer to your question is 8 cm diameter, increasing to 16 cm diameter: r2 squared = 4 x r1 squared and r2 = r1 + 4 r1 squared + 8r1 + 16 = 4r1 squared 3r1 squared - 8r1 - 16 = 0 Factors are (3r1 + 4)(r1 - 4), so original radius was 4cm (area 16pi) and increased radius is 8 cm (area 64pi).