We cannot find out the y and x intercept for the equation 3x plus 5y equals -15 by a single equation . But , we can try a hit and trial method for the same . when x =0 y =-3. when y=0 x=-5.
X^2 + Y^2 = 36 Y^2 = 36 - X^2 Y = (+/-)sqrt(36 - X^2) A circle. X = (+/-) 6 Y = (+/-) 6
x + 7 + y
x + y + z = x + z + y is the commutative property of addition.
X = 135 and y = 15 Solved by addition and substitution
We cannot find out the y and x intercept for the equation 3x plus 5y equals -15 by a single equation . But , we can try a hit and trial method for the same . when x =0 y =-3. when y=0 x=-5.
The given expression is the same as 15+x+y simplified
Your question is like this:X+Y=15, X-Y=5, (X x Y)-X+Y= ?According to my calculations, X=10 and Y=5, therefore (X x Y)-X+Y= 45.
x intercept = 5 y intercept = 15
15 (x = 135)
15
Assuming the equation is 3x + y = 15, then the x-intercept is (5, 0) and the y-intercept is (0, 15).
x = 11 y = 16
(1) x+y=15(2) 4x+3y=38From (1) one gets x=15 -y, put into(2)4(15-y)+3y=3860-4y+3y=3860-y=38y=22 then x=15-y=-7(-7,22) is the solution
x+y=15, or y=15-x4x+3y=38Substitute y in 2nd equation with 15-x:4x+45-3x=38x=-7y=15-(-7)=22(-7,22)
-3x + 5y = -15At the x-intercept, y=0:-3x = -15 . . . . . x = 5At the y-intercept, x=0:5y = -15 . . . . . y = -3
It is: y = 5x+15