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How do you solve the quadratic equation t2 4t equals 21 by factoring?
Subtract 21 from both sides. If that's + 4t, the answer is (t - 3)(t + 7) and t = 3, -7 If that's - 4t, the answer is (t + 3)(t - 7) and t = -3, 7
What is 7 6 t 7 6 t?
If the question is answered by the true algebra rule of how you have wrote it, then the answer will be as follows: 7 * 6 = 42 * t = 42t * 7 = 294t * 6 = 1764t * t = 1764t2
Edward is t years old now express his age 7 years ago?
T-7 years old
Factor 77-18T plus T2?
(t - 7)(t - 11)
Given sin theta equals 7 over 13 and tan theta is less than 0 find tan theta?
sin(t) = 7/13 cos2(t) = 1 - sin2(t) = (169 - 49)/169 = 120/169 so cos(t) = ±sqrt(120)/13. But sin(t) > 0, tan(t) < 0 implies t is in the second quadrant so cos(t) = -sqrt(120)/13 And then tan(t) = sin(t)/cos(t) = -7/sqrt(120) = -0.6390 (approx).
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