HCF(8, 6) = 2.
The Highest Common Factor (HCF) of 8 and 24 is 8. To find the HCF, you need to determine the largest number that divides both 8 and 24 without leaving a remainder. In this case, 8 is the largest number that divides both 8 and 24 evenly, making it the HCF.
factors of 8: 1, 2, 4, 8 factors of 18: 1, 2, 3, 6, 9, 18 HCF: 2
49 = 7 x 7, 21 = 7 x 3, 91 = 7 x 13. HCF is 7
8
1
The HCF of the given numbers is 1
The highest common factor (HCF) of 7, 8, and 10 is 1. This is because the only factor that these three numbers share is 1, as 7, 8, and 10 do not have any other common factors. Therefore, the HCF of 7, 8, and 10 is 1.
hcf(16×27×49, 8×2725) = 8×27 = 216 Using prime factorisation: 16×27×49 = 2⁴ × 3³ × 7² 8×27×125 = 2³ × 3³ × 5³ → hcf = 2³ × 3³ = 8×27 = 216
The HCF is 7.
30 -> 1,2,3,5,6,10,15,30 210 -> 1,2,3,5,6,7,10,14,15,21,30,35,42,70,105,210 700 -> 1,2,4,5,7,10,20.25,28,35,70,100,140,175,350,700 GCF is 10
The Highest Common Factor (HCF) of 64 and 56 is 8. To find the HCF, you can determine the factors of both numbers: 64 (1, 2, 4, 8, 16, 32, 64) and 56 (1, 2, 4, 7, 8, 14, 28, 56). The largest number that appears in both lists is 8, making it the HCF of 64 and 56.
The GCF is 7.
The GCF is 7.
HCF(8, 6) = 2.
The GCF is 7.
The GCF is 1.