The HCF of the given numbers is 1
hcf(16×27×49, 8×2725) = 8×27 = 216 Using prime factorisation: 16×27×49 = 2⁴ × 3³ × 7² 8×27×125 = 2³ × 3³ × 5³ → hcf = 2³ × 3³ = 8×27 = 216
It is: 1
The highest common factor (HCF) of 7, 8, and 10 is 1. This is because the only factor that these three numbers share is 1, as 7, 8, and 10 do not have any other common factors. Therefore, the HCF of 7, 8, and 10 is 1.
5.. divides into 5 and 10.
HCF is the highest common factor of two or more numbers. HCF of 25 and 40 is 5.
The Highest Common Factor (HCF) of 210 and 112 is the largest positive integer that divides both numbers without leaving a remainder. To find the HCF, you can use the Euclidean algorithm or prime factorization method. In this case, the prime factorization of 210 is 2 x 3 x 5 x 7, and the prime factorization of 112 is 2^4 x 7. The common factors are 2 and 7, so the HCF is 2 x 7 = 14.
35. 350 = 2 x 52 x 7 385 = 5 x 7 x 11 hcf = 5 x 7 = 35
Prime factors of 210 are: 2, 3, 5 and 7 Prime factors of 385 are: 5,7 and 11 Common factors are: 5 and 7 and so 5*7 = 35 which is the hcf
The HCF is 1
hcf(490, 1750) = 70 Using factorisation: 490 = 2 x 5 x 7² 1750 = 2 x 5³ x 7 hcf = 2 x 5 x 7 = 70
The GCF is 42.