HCF(10, 84) = 2 HCF(10, 84) = 2 HCF(10, 84) = 2 HCF(10, 84) = 2
The HCF of the given numbers is 1
hcf(16×27×49, 8×2725) = 8×27 = 216 Using prime factorisation: 16×27×49 = 2⁴ × 3³ × 7² 8×27×125 = 2³ × 3³ × 5³ → hcf = 2³ × 3³ = 8×27 = 216
The HCF is 7.
The one-step method is to find the highest common denominator HCF of the numerator (top) and denominator (bottom) of the fraction and divide both of them by the HCF. If you don't know how to find the HCF just find any number that divides both the numerator and the denominator and divide both by that number. Then repeat and keep repeating until there is no number (other than 1 ) that divides both. So 8/10 HCF(8, 10) = 2 Therefore, simplified 8/10 = 8/2 divided by 10/2 = 4/5
30 -> 1,2,3,5,6,10,15,30 210 -> 1,2,3,5,6,7,10,14,15,21,30,35,42,70,105,210 700 -> 1,2,4,5,7,10,20.25,28,35,70,100,140,175,350,700 GCF is 10
The GCF is 2.
1
It is: 1
HCF(8, 10) = 2
The GCF is 8.
5.. divides into 5 and 10.
It is 1 but the HCF is 2
The GCF is 7.
HCF(10, 84) = 2 HCF(10, 84) = 2 HCF(10, 84) = 2 HCF(10, 84) = 2
The HCF of the given numbers is 1
The HCF is '10'