Add 5 in mod 8.
(You can always subtract 3 in mod 8 as well, eg 5 + 3 = 0; 0 - 3 = 5.)
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To form the additive inverse, negate all parts of the complex number → 8 + 3i → -8 - 3i The sum of a number and its additive inverse is 0: (8 + 3i) + (-8 - 3i) = (8 + -8) + (3 + -3)i = (8 - 8) + (3 - 3)i = 0 + 0i = 0.
The additive inverse of a number is the value that, when added to the original number, results in a sum of zero. In this case, the additive inverse of 22 would be -22, as 22 + (-22) equals zero. The additive inverse is essentially the negative version of the original number.
do you mean y = 2x + 8 ? the inverse is y = (x - 8)/2
The inverse for f(x) = 4x + 8 isg(x) = x/4 - 2
y = 3x + 8Replace x with y and y with x.x = 3y + 8Solve for y.x - 8 = 3y3y = x - 8y = (x-8)/3