To form the additive inverse, negate all parts of the complex number
→ 8 + 3i → -8 - 3i
The sum of a number and its additive inverse is 0:
(8 + 3i) + (-8 - 3i) = (8 + -8) + (3 + -3)i = (8 - 8) + (3 - 3)i = 0 + 0i = 0.
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Just change every plus to minus, and every minus to plus. In this case, if you mean 8 + 3i, change it to -8 - 3i.As a check, the original number, plus its additive inverse, must have a sum of zero.
The additive inverse is x5 + 2x - 2.
If you mean the ADDITIVE INVERSE, change the minus sign to a plus sign. (And if you see a plus sign, you change it to a minus sign.)
Oh, dude, the additive inverse of -12 is just 12. It's like the positive version of that negative number, you know? So if you owe someone -12 dollars, just give them 12 bucks and call it even. Easy peasy lemon squeezy.
The multiplicative inverse of a complex number is the reciprocal of that number. To find the multiplicative inverse of 4 + i, we first need to find the conjugate of 4 + i, which is 4 - i. The product of a complex number and its conjugate is always a real number. Therefore, the multiplicative inverse of 4 + i is (4 - i) / ((4 + i)(4 - i)) = (4 - i) / (16 + 1) = (4 - i) / 17.
This is the existence of additive inverse: For every number, x, there exists a number, denoted by (-x), such that x + (-x) = (-x) + x = 0.