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The additive inverse is x5 + 2x - 2.
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∙ 10y ago
Nehemiah Ortega
Nehemiah Ortega
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What is the inverse of the equation y equals 2x plus 3?
x=(y-3)/2
What is the inverse of y 2x8?
do you mean y = 2x + 8 ? the inverse is y = (x - 8)/2
How do you solve x - x x?
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
How do you solve 2x plus 2?
The solution to the equation 2x plus 2 is 2(x + 1).
3x plus 5x equals 2x plus 2?
3x + 5x = 2x + 28x = 2x + 26x = 2x = (2/6) = 1/3
What is the expntents of x5 - 3x4 plus x2 - 4 plus 5x4 plus 3x2 plus 2x plus 1?
x^5+2x^4+4x^2+2x-3
Inverse function 2x plus 4?
y=2x+4 --> x=2y+4 ==> y=(x-4)/2
What is the inverse of the equation y equals 2x plus 3?
x=(y-3)/2
2x plus x plus opposite x plus -1 equals 7 plus 2 opposite x?
This is an unclear equation, actually some sort of addition. (Opposite means negative? Inverse?) 2x + x + (-x) + (-1) = 7 + 2 (-x) ?? 2x - 1 = 7 - 2x 4x = 8 x = 2
How do you factor -x5-x3 plus 6x?
-x(x2 - 2)(x2 + 3)
How do you find the inverse of the function f of x equals 2x plus 1 divide x-1?
y = f(x) = (2x + 1)/(x - 1)y*(x - 1) = (2x + 1) xy - y = 2x + 1xy - 2x = y + 1x(y - 2) = y + 1so x = (y + 1)/(y - 2) assuming y�2.So the inverse function is f-1(x) = (x + 1)/(x - 2)
What is the inverse of y 2x8?
do you mean y = 2x + 8 ? the inverse is y = (x - 8)/2
Which polynomials are listed with their correct additive inverse X2 plus 3x-2-x2-3x plus 2 Y7-10-y7 plus 10 6z5 plus 6z5-6z4(-6z5) plus (-6z5) plus 6z4 X-11-x (-5x2) plus (-2x) plus (-10)5x2-2x plus 1?
x^2 + 3x - 2; -x^2 - 3x + 2andx - 1; 1 - x
How do you solve x - x x?
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
What is the inverse of fx equals 2x?
g(x) = x/2
Can you tell the difference between the arigonal equation and the inverse?
I would say that functions have inverses, rather than equations.One simple way to find the inverse of a function is to switch the x and y:The inverse of y = (3x+5)/2 is . . . x = (3y+5)/2.You can take this inverse and solve it for y: (2)x=(2)(3y+5)/2 2x=3y+5 3y+5=2x 3y=2x-5 y=(2x-5)/3.Notice that in the original you multiply by 3, add 5, and divide by 2. On the inverse, you multiply by 2, subtract 5, and divide by 3. You do the inverse operations in the reverse order.
4-2x plus 7 plus 1 plus 2x plus 2?
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