.6853 radians or 39.2644 degrees.
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sin of angle a = opposite/hypotenuse = 1/3 sin-1(1/3) = 19.47122063 degrees
Assuming the angle is given in radians, it is -0.9939
Area = 1/2*a*b*sin(C) where a = BC, b = AC and angle C = angle BCA 27 = 0.5*12*AC*sin(98) So AC = 27/[0.5*12*sin(98)] = 4.54 approx.
sin θ = cos (90° - θ) cos θ = sin (90° - θ)
I think you have not asked the question correctly.I guess you meant that the sides of the triangle are 3, 4 and 5. Similarly you have given no indication of which angle is opposite which side.A 3, 4, 5 triangle is a right angle triangle (5 is the hypotenuse).Thus depending where angle B is, its sine will be:If B is opposite the side of length 3, sin B = 4/5If B is opposite the side of length 4, sin B = 3/5If B is opposite the side of length 5, sin B = 5/5 = 1; alternatively ∠B = 90° and sin B = sin 90° = 1