3x - 5x + x = -x
5x cubed
-4
sorry i am not sure but i dont think it has an answer If this equation is: x^2 - 36 = 5x, then: x^2 - 36 = 5x subtract 5x to both sides; x^2 - 5x - 36 = 0 Factor; (x + 4)(x - 9) = 0 x + 4 = 0 or x - 9 = 0 x = -4 or x = 9
No comment
int x ln5x dx by parts u = ln5x du = 1/5x or 5x^-1 dv = x v = 1/2x^2 uv - int v du ln5x 1/2x^2 - int 1/2x^2 5x^-1 1/2ln5x*x^2 - 1/6x^3 5x + C
-(v + 5)(w - x)
5x + x = 5x Squared (5x^2) x + x equals 2 x's = 2 = squared - very simple & logic. no its not simple and logic 5x^2 is the result of 5x times x. 5x plus x is 6x. Think of the x as 1x not x so 1x + 5x= 6x. That's simple and logic.
x = .5x - 4. Get all of the x's on one side: x - .5x = .5x - .5x -4 ---> .5x = -4 Multiply each side by 2. x = -8
3
5x x 4x = 20x^2 5x + x + 4x = 10x
3x - 5x + x = -x
Assuming the angles are expressed in radians:sin(5x) + sin(x) = 0∴ sin(5x) = -sin(x)∴ 5x = x + π∴ x = π/4On the other hand, if your angles are in degrees, then the answer would be:sin(5x) + sin(x) = 0∴ sin(5x) = -sin(x)∴ 5x = x + 180∴ x = 180°/4∴ x = 45°
5x² - 18x + 9 = (5x² - 15x) - (3x - 9) = 5x(x - 3) - 3(x - 3) = (5x - 3)(x - 3).
5x+x >100
-43
integration by parts. Let u=lnx, dv=xdx-->du=(1/x)dx, v=.5x^2. Integral of (xlnxdx)=lnx*.5x^2-integral of .5x^2(1/x)dx=lnx*.5x^2-integral of .5xdx=lnx*.5x^2-(1/6)x^3. That's it.