4a-2 (if a=3) 4•3-2 12-2 10......so 4a-2=10
Solve the following equation for A : 2A/3 = 8 + 4A
3a2
x/2 = x/5 + 1 5x = 2x + 10 3x = 10 x = 3 1/3
If the questions asks: (3)/(4x+2) = (5)/(4x-6) then x = -(7/4)
5
4a-2=7a-6 4=3a a=4/3
4a+3-a =12 4a-a = 12-3 3a = 9 a = 3
4a - 5 = 7a - 7 -5 = 3a - 7 2 = 3a a = 3/2
4a x 3
2a*3 = 8+4a 6a = 8+4a 6a-4a = 8 2a = 8 a = 4
a=5
2 over 3 equals 8 over 12
Not sure why it is 3a2- if you mean 3*a*2, then: 3*a*2=6a (6a-2a)+5-2(a (or a2)+a)=1 4a+5-(2a+a)=1 4a+5-2a-a=1 Then take the 5 over (remember, the +5 become -5 when transposed): 4a-2a-a=1-5 Solving the equations on both sides gives: a=-4 Is this your answer?
Add the equations: 4a + 4a - 5b + 5b = 7 + 17 ie 8a = 24 a = 3, so b = 1
4a+3 when a=34(3)+312+3=15So you are substituting(replacing) 'a' with the known value of '3'. You then multiply the '4' with the '3' because of the placing of 'a'.
It equals to 3 over 2