As you have written it '' - 4x 8 ' it means nothing.
However, if you mean ' -4x = 8 ' . (Note the 'equals(=)' sign.
Then Dividie both sides by '-4'
Hence
-4x/-4 = 8/-4
Cancel down by '-4'
x = -2 ( Note it is 'minus(-) 2'. NOT (+)2.
If: 4x+(-12) = 8 then 4x = 20 and x = 5
2y = 4x - 16 5y = 4x + 8 Subtract the first equation from the second: 3y = 24 so that y = 8 Substitute this into the first equation: 16 = 4x - 16 ie 32 = 4x so that x = 8 So the solution is (8, 8)
4x + 5y = -8 is an equation with two variables. While you can solve for y = something, you won't come up with a single number. For example, 4x + 5y = -8 5y = -4x - 8 y = -4x/5 - 8/5. And you can do the same for x = something in terms of y.
Presumably this is an equation in which the value of x is to be found. 7x+8 = 4x-10 7x-4x = -10-8 3x = -18 x = -6
5-4x=x-35-4x+4x=x-3+4x (adding 4x on both side)5=5x-35+3=5x-3+3 (adding 3 on both side)8=5xx=8/5
2(4x + 4) = (4x - 12) 8x + 8 = 4x - 12 8x - 4x + 8 = 4x - 4x - 12 4x + 8 = -12 4x + 8 - 8 = -12 - 8 4x = -20 4x/4 = -20/4 x = -5
4x -8 = -4
8 + y = 4x8 + y - 4x = 4x - 4x 8 + y - 4x = 0 8 - 4x + y = 0
-4x + 8 = -4 -4x + 8 - 8 = -4 -8 -4x = -12 -4x/-4 = -12/-4 x = 3
4x-3-8 = 8 4x = 8+8+3 4x = 19 x = 4 and 3/4
8-3x-x = 12 8-4x = 12 -4x = 12-8 -4x = 4 x = -1
(4x-8)2 = (4x-8)(4x-8) = 16x2-32x-32x+64 = 16x2-64x+64
If: 4x+(-12) = 8 then 4x = 20 and x = 5
4x - 3 = 8
4x - 8 = 16 Add 8: 4x = 24 Divide by 4: x = 6
If the equation is y = 4x + 8, then the standard form is 4x - y + 8 = 0
y = 2x^(2) + 4x + 8 dy.dx = 2(2)x^(2-1) + 4x^(1-1) +8x^(0) dy/dc = 2(2)x^(1) + (1)4x^(0) + (0)8x^(0-1) dy/dx = 4x + 4 + 0 dy/dx = 4x + 4 *The derivative). NB #1 The original index number becomes a coefficient ( in brackets). Then subtract '1' from the original index value, for the new index value. #2 Any term raised to the power of '0' = 1. #3 Any term multiplied by '0' = 0.