5-4x=x-3
5-4x+4x=x-3+4x (adding 4x on both side)
5=5x-3
5+3=5x-3+3 (adding 3 on both side)
8=5x
x=8/5
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2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
y2=x3+3x2
x3 + 8 = x3 + 23 = (x + 2)[x2 - (x)(2) + 22] = (x + 2) (x2 - 2x + 4)
x3 - 3x2 + x - 3 = (x2 +1)( x - 3)
The anti-derivative of X2 plus X is the same as the anti-derivative of X2 plus the anti-derivative of X. The anti derivative of X2 is X3/3 plus an integration constant C1 The anti derivative of X is X2/2 plus an integration constant C2 So the anti-derivative of X2+X is (X3/3)+(X2/2)+C1+C2 The constants can be combined and the fraction can combined by using a common denominator leaving (2X3/6)+(3X2/6)+C X2/6 can be factored out leaving (X2/6)(2X+3)+C Hope that helps