2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
y2=x3+3x2
x3 + 8 = x3 + 23 = (x + 2)[x2 - (x)(2) + 22] = (x + 2) (x2 - 2x + 4)
The anti-derivative of X2 plus X is the same as the anti-derivative of X2 plus the anti-derivative of X. The anti derivative of X2 is X3/3 plus an integration constant C1 The anti derivative of X is X2/2 plus an integration constant C2 So the anti-derivative of X2+X is (X3/3)+(X2/2)+C1+C2 The constants can be combined and the fraction can combined by using a common denominator leaving (2X3/6)+(3X2/6)+C X2/6 can be factored out leaving (X2/6)(2X+3)+C Hope that helps
x3 - 3x2 + x - 3 = (x2 +1)( x - 3)
It is an algebraic expression.
Yes.
Since that isn't an equation, there is really nothing to solve.
x3+36 is an algebraic expression
It is 4 terms of an algebraic expression.
x(x4+x3+x2+x+1)
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
x3 = x times x times x 3x = x plus x plus x
The expression of 5x3+6-x3 can simplified to 4x3+6
X3 + 13X2 + 40X factor out an X X(X2 + 13X + 40) factor the quadratic expression, what two factors of 40 add up to 13? X(X + 8)(X + 5) works the same if that is a negative in front of X3, just sign changes
Anything plus 0 is itself, so x3 + 0 is x3.
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)