y times y times y (or y3)
Differentiating with respect to one variable means thinking of all the other variables as constants. The answer is thus y=0.
They don't seem to different at first. But the thing is, Y3 is outdated and old. It may still have the original database of Y8, but Y3 is older. If you notice the layout of the new Y8, it is newer and more user friendly. Plus a really world-known game, Bloons Tower Defense, can't be found on Y3 easily, while Y8 brings the searches instantly. Y8 is better than Y3.
y5 * y3 * y = y5 * y3 * y1 = y5+3+1 = y9
6x+y=3
72
no
y3 x y3 - y (3)3 x 3(3) - 3 9 x 9 - 3 = ? 9 x 9= 81 81 - 3 = 78 I hope that solves your problem
4y + 19 = 74y = 7-194y = -124y/4 = -12/4y = -3
3xyz
Lets start by putting the known number on the other side. Y3 -7500y=125000. There is your start. Take it from here.
y=3 y^3(y^3-y)= 3^3(3^3-3)= 27(27-3)= 27(24)=648
One equation with two unknowns usually does not have a solution.
6y-y3 = 3
If one of them and the other One is exactly the same(capital,letters) then it is equal:D
-y3 + 7y3
x3-y3