The answer is 2. 2x = 2x1 So you follow the usual rule about bring down the exponent and subtract one from it and you get 1*2x0= 2x0=2
1 dekaliter equals to 10 liters
Which means 0 = -1!
(1, -1)
One multiplied by one equals one. This is because any number that is multiplied by one equals itself. In this case, it equals one.
x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
The differential of the product xy with respect to x is y + x dy/dx. The differential of logy with respect to x is (1/y) dy/dx. The role of c in this question is not made clear.
The derivative of ( x1/2 ) with respect to 'x' is [ 1/2 x-1/2 ], or 1/[2sqrt(x)] .
With respect to x, the derivative would be:1*Y^3 = Y^3With respect to Y the derivative would be:3*xy^2 - 3In general: the derivative of a variable is defined as: nax^n-1Where n represents the power, a represents the factor and x represents the variable
The derivative with respect to x of any term in this format: axn is equal to: nax(n -1) so in the case of x2, the answer will be: 2x(2 - 1) = 2x1 = 2x
It is the identity property of 1 with respect to multiplication.
The answer is 2. 2x = 2x1 So you follow the usual rule about bring down the exponent and subtract one from it and you get 1*2x0= 2x0=2
1/2x
OK. That's the equation of a parabola, symmetrical with respect to the x-axis, opening downward, with its nose at y=1. What's the question ?
Your question is pretty ambiguous. First of all, the natural logarithm is a function and requires a variable to be input into it. Secondly, the process of differentiation is a type of transformation or operation performed on a function, and it is done with respect to a particular variable. Its important when you ask questions in math that you ask a full, explicit question."How do you differentiate, with respect to x, the function ln(x)" would be more proper.Or simply do it in math:d/dx ln(x)============The answer to the question is simple. It is 1/x.d/dx ln(x) = 1/x
My suggestion is to multiply the binomials and do the integration directly, and then differentiate the result with respect to x. (If that doesn't work, feel free to send me a picture of the problem and I'll give it another try.)
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