x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
5=3x+2 3x+2-2=5-2 3x=3 ------ 3 x=1
5x-2 = 3x-6 5x = 3x - 6 +2 5x = 3x - 4 5x - 3x = -4 2x = -4 x = -2
(3x2 - 6x)/3x = 3x(x-2)/3x = x-2, for x<>0
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
9x2 + 12x + 4 = 9x2 + 6x + 6x + 4 = 3x(3x + 2) + 2(3x + 2) = (3x + 2)(3x + 2) = (3x + 2)2
If 2 divided by 3x it is equal to 2/3x
If you mean: 9x2+3x-2 = (3x+2)(3x-1) when factored
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
5=3x+2 3x+2-2=5-2 3x=3 ------ 3 x=1
3x + 2 = 3x + 6 This is not possible.
3x+2.
-(3x -2) = 17 -3x + 2 = 17 - 3x = 15 x = -5
I think you mean to solve:(-2 cos23x) - (3 sin 3x) = 0cos2 x + sin2 x = 1⇒ cos2x = 1 - sin2 x⇒ -2 cos2 3x - 3 sin 3x = -2(1 - sin2 3x) - 3 sin 3x = 0⇒ 2 sin2 3x - 3 sin 3x - 2 = 0⇒ (2 sin 3x + 1)(sin 3x - 2) = 0⇒ sin 3x = -1/2 or 2sin 3x = 2 is impossible as the range of sine is -1 ≤ sine ≤ 1Thus:sin 3x = -1/2⇒ 3x = 2nπ - π/6 or 2nπ - 5π/6⇒ x = 2/3nπ -π/18 or 2/3nπ -5π/18
5