While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
(3x + 1)(x - 4)
Factor: 9x2 - 25.
9x2 + 9x - 10 =(3x - 2)(3x + 5)
9x2+2x-7 = (9x-7)(x+1) when factored
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
3x2(x2 - 3)
Assuming all the missing operational signs are pluses, that factors to (x + 3)(3x2 + 1)
-6x + 9x2 - 24 = 3(3x2 - 2x - 8) = 3(3x2 - 6x + 4x - 8) = 3(3x(x - 2) + 4(x - 2)) = 3(3x + 4)(x - 2)
Given, 3x2 - 4x = -2 Then, 9x2 - 12x = -6; 9x2 - 12x + 4 = -2 {completing the square} ; 3x - 2 = ±i√2 {sq rt of both sides} ; and 3x = 2 ± i√2. Therefore, x = ⅓(2 ± i√2).
1
3x2 - 2y2 = 9x2 + 4y2 - 12xy (subtract 3x2 and add 2y2 to both sides) 0 = 9x2 -3x2 + 4y2 + 2y2 - 12xy 0 = 6x2 + 6y2 - 12xy (divide by 6 to both sides) 0 = x2 + y2 - 12xy or x2 - 2xy + y2 = 0 (x - y)(x - y) = 0 x - y = 0 x = y
(3x2 + 2x + 1)
9x2 - 18x = -3x2 - 2x = -1/3x2 - 2x + 1 = 1 - 1/3(x - 1)2 = 2/3x - 1 = ±√2/3x = 1 ± (1/3)√6)
GCF is 9x2
6= 3x2 2x3