Without knowing the plus or minus values of the given terms and without any equality signs it can't be considered as a system of equations.
Without any equality signs the given expressions can't be considered to be equations.
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
(3, 6)-------------------Let's see.(6) = 3(3) - 33(3) - (6) = 36 = 9 - 39 - 6 = 36 = 63 = 3========== (3, 6) is a solution to the system of equations. The only solution? I do not know.
No. Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
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Which of the following best describes the solution to the system of equations below?3x + 6y = 10 9x + 18y = 30
If you mean: 3x-4y = 19 and 3x-6y = 15 Then: x = 9 and y = 2
Without any equality signs the given expressions can't be considered to be equations.
If "equations-" is intended to be "equations", the answer is y = -2. If the first equation is meant to start with -3x, the answer is y = 0.2
Symbols not visible. Please resubmit using words eg "plus", "equals" etc
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
(3, 6)-------------------Let's see.(6) = 3(3) - 33(3) - (6) = 36 = 9 - 39 - 6 = 36 = 63 = 3========== (3, 6) is a solution to the system of equations. The only solution? I do not know.
Without any equality signs the given terms can't be considered to be equations
Without any equality signs the given terms can't be considered to be equations.
No. Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
Which system of inequalities has no solution?A.y > 3x - 1y < 3x - 3B.y > 3x + 3y < 3x + 7C.y > -1y < 2y > 2x - 3re...