cot2x-tan2x=(cot x -tan x)(cot x + tan x) =0
so either cot x - tan x = 0 or cot x + tan x =0
1) cot x = tan x => 1 / tan x = tan x => tan2x = 1 => tan x = 1 ou tan x = -1
x = pi/4 or x = -pi /4
2) cot x + tan x =0 => 1 / tan x = -tan x => tan2x = -1
if you know about complex number then infinity is the solution to this equation, if not there's no solution in real numbers.
There is no value cot 0, because cot 0 is equivalent to 1 / tan 0, which is equivalent to 1 / 0, which is undefined. That said, the limit of cot x as x approaches 0 is infinity.
x = -½
That factors to (x - 2)(x + 7)
So u have the function x2-4=0 Now because 4 is a squared number, its square root is 2 (x+2)(x-2)=0
5x2 - 20 = 0x2 - 4 = 0x2 = 4x = +2 and -2
either cos OR tan-sin equals zero socos=0 at pi/2 and 3pi/2ortan=sin which is impossibleim not sure though
You cannot because cot(0) is not defined, neither is cosec(0).
Cot(90) = 0 so 1/cot(90), if defined, would be 1/0. Such a fraction is not defined and that is what is wrong with the sentence.
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
There is no value cot 0, because cot 0 is equivalent to 1 / tan 0, which is equivalent to 1 / 0, which is undefined. That said, the limit of cot x as x approaches 0 is infinity.
Tan of 0 equals zero.
sin(0) = 0, sin(90) = 1, sin(180) = 0, sin (270) = -1 cos(0) = 1, cos(90) = 0, cos(180) = -1, cos (270) = 0 tan(0) = 0, tan (180) = 0. cosec(90) = 1, cosec(270) = -1 sec(0) = 1, sec(180) = -1 cot(90)= 0, cot(270) = 0 The rest of them: tan(90), tan (270) cosec(0), cosec(180) sec(90), sec(270) cot(0), cot(180) are not defined since they entail division by zero.
0 squared is 0. Zero times zero equals zero.
It equals 0. Zero times zero equals zero.
Let x = theta, since it's easier to type, and is essentially the same variable. Since tan^2(x)=tan(x), you know that tan(x) must either be 1 or zero for this statement to be true. So let tan(x)=0, and solve on your calculator by taking the inverse. Similarly for, tan(x)=1
(sin(x)cot(x) - cos(x))/tan(x)(Multiply by tan(x)/tan(x))sin(x) - cos(x)tan(x)(tan(x) = sin(x)/cos(x))sinx - cos(x)(sin(x)/cos(x))(cos(x) cancels out)sin(x) - sin(x)0
x squared -2x-3 equals 0 is the same as (x + 1)(x - 3) = 0