cot2x-tan2x=(cot x -tan x)(cot x + tan x) =0
so either cot x - tan x = 0 or cot x + tan x =0
1) cot x = tan x => 1 / tan x = tan x => tan2x = 1 => tan x = 1 ou tan x = -1
x = pi/4 or x = -pi /4
2) cot x + tan x =0 => 1 / tan x = -tan x => tan2x = -1
if you know about complex number then infinity is the solution to this equation, if not there's no solution in real numbers.
There is no value cot 0, because cot 0 is equivalent to 1 / tan 0, which is equivalent to 1 / 0, which is undefined. That said, the limit of cot x as x approaches 0 is infinity.
x = -½
That factors to (x - 2)(x + 7)
So u have the function x2-4=0 Now because 4 is a squared number, its square root is 2 (x+2)(x-2)=0
5x2 - 20 = 0x2 - 4 = 0x2 = 4x = +2 and -2
either cos OR tan-sin equals zero socos=0 at pi/2 and 3pi/2ortan=sin which is impossibleim not sure though
You cannot because cot(0) is not defined, neither is cosec(0).
Cot(90) = 0 so 1/cot(90), if defined, would be 1/0. Such a fraction is not defined and that is what is wrong with the sentence.
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
There is no value cot 0, because cot 0 is equivalent to 1 / tan 0, which is equivalent to 1 / 0, which is undefined. That said, the limit of cot x as x approaches 0 is infinity.
Tan of 0 equals zero.
0 squared is 0. Zero times zero equals zero.
sin(0) = 0, sin(90) = 1, sin(180) = 0, sin (270) = -1 cos(0) = 1, cos(90) = 0, cos(180) = -1, cos (270) = 0 tan(0) = 0, tan (180) = 0. cosec(90) = 1, cosec(270) = -1 sec(0) = 1, sec(180) = -1 cot(90)= 0, cot(270) = 0 The rest of them: tan(90), tan (270) cosec(0), cosec(180) sec(90), sec(270) cot(0), cot(180) are not defined since they entail division by zero.
No, it equals 0. If you have nothing, and you multiply it by nothing, you still have nothing.
It equals 0. Zero times zero equals zero.
x squared -2x-3 equals 0 is the same as (x + 1)(x - 3) = 0
Let x = theta, since it's easier to type, and is essentially the same variable. Since tan^2(x)=tan(x), you know that tan(x) must either be 1 or zero for this statement to be true. So let tan(x)=0, and solve on your calculator by taking the inverse. Similarly for, tan(x)=1