Let x = theta, since it's easier to type, and is essentially the same variable. Since tan^2(x)=tan(x), you know that tan(x) must either be 1 or zero for this statement to be true. So let tan(x)=0, and solve on your calculator by taking the inverse. Similarly for, tan(x)=1
Tan^2
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
The tangent function (tan) in trigonometry is defined as the ratio of the length of the opposite side to the length of the adjacent side in a right triangle. Mathematically, it can be expressed as ( \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} ). Additionally, in terms of sine and cosine, ( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} ), where ( \theta ) is an angle in a right triangle or in the unit circle.
4
If tan theta equals 2, then the sides of the triangle could be -2, -1, and square root of 5 (I used the Pythagorean Theorem to get this). From this, sec theta is negative square root of 5. It is negative because theta is in the third quadrant, where cosine, secant, sine, and cosecant are all negative.
It also equals 13 12.
Tan^2
Yes, it is.
Yes. (Theta in radians, and then approximately, not exactly.)
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
0.75
tan3A-sqrt3=0 tan3A=sqrt3 3A=tan^-1(sqrt3) 3A= pi/3+npi A=pi/9+npi/3 n=any integer
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
I assume. Since theta is a variable, standing for the measure of any angle.
1 - sin2(q) = cos2(q)dividing through by cos2(q),sec2(q) - tan2(q) = 1
I'm asuming you meant "ten theta"the square of 5 is 2525 divided by 10 is 2.5so theta equals 2.5there you go =)