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I will assume that you mean log base 3 to 10. So 3 to the power of what equals 10?
The answer is not rational, that is it cannot be expressed in terms of m/n where m is an integer, n is a natural number.
So there is only one way to write it, the proper definition way. i.e. log (3) 10
(log base 3 to 10)
Improved Answer:-
log3(10) = 2.0959032743 because 32.0959032743 = 10
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Log3 81 x log2 8 x log4 2 equals x?
log3 81 × log2 8 × log4 2 = log3 (33) × log2 (23) × log4 (40.5) = 3 × (log3 3) × 3 × (log2 2) × 0.5 × (log4 4) = 3 × 1 × 3 × 1 × 0.5 × 1 = 9 × 0.5 = 4.5
How do you input log base 3 in a calculator?
Let y = log3 x⇒ x = 3yTaking logs to any base you like of both sides gives:log x = y log 3⇒ y = log x/log 3So to calculate log base 3 on a calculator, use either the [log] (common or log to base 10) or [ln] (natural or to base e) function key for the log above, that is use one of:[(] [log] [] [÷] [log] [3] [)][(] [ln] [] [÷] [ln] [3] [)][(] [] [log] [÷] [3] [log] [)][(] [] [ln] [÷] [3] [ln] [)]Things in square brackets [] represent keys on the calculator; the is the number of which you want the logarithm to base 3.Use one of 1 & 1 if your calculator is a more modern one that uses natural representation that looks like maths whereby the calculation is done once you've finished entering it all and the numbers for functions follow them.Use one of 3 & 4 if your calculator is an older style one that when you press a function key it acts immediately on the number displayed on the screen.The parentheses (round brackets) are included above so that the whole expression evaluates to log3.
What is ten times 10?
10x10=10010+10+10+10+10+10+10+10+10+10=10010 times 10 is 100.
Damath chips of level II board?
0, -1/10, 2/10, -3/10, 4/10, -5/10, 6/10, -7/10, 8/10, -9/10, 10/10, -11/10
What does 10 x 10 x 10 x 10 x10 x 10 x 10 equals?
10 x 10 x 10 x 10 x10 x 10 x 10 =10,000,000
Log3 10 log3 x -13?
10log3
What is log3 9root3?
log3 [ 9 sqrt(3) ]= log3 [ 9 ] + log3 [ sqrt(3) ]= log3 [ 32 ] + log3 [ 31/2 ]= 2 + 1/2= 2.5
How do you solve Log base 3 of 7x equals Log base 3 of 2x plus Log base 3 of 0.5?
There is not a solution. Knowing how logarithms work helps. On the right hand side you have: log3(2*x) + log3(0.5).Adding logs is equivalent to multiplying (inside the log). This becomes: log3(0.5 * 2*x) = log3(x).Subtract log3(x) from both sides: log3(7x) - log3(x) = 0.Subtracting logs is equivalent to division (inside the log): log3(7x/x) = 0.So log3(7) = 0, which is Not true. No Solution.
How do you solve this log x base 3 plus log x3 base 9 equal 0?
log3(x) + log9(x^3)=0 for any t >0 logt(x) = ln(x)/ln(t) so log9(x) = ln(x) / ln (9) = ln (x) / ( 2 * ln 3) = log3(x) /2 or log3(x) = 2 log9(x) log9(x^n) = n * log9(x) So log3(x) + log9(x^3) = log3(x) + 6 log3(x) = 7 log3(x) 7 log3(x) = 0 => log3(x) = 0 => x = 1
How do you simplify log base 3 25 plus log base 3 4 and express using base 10 logarithms?
log325 + log34 = log3(25*4) = log3(100) = log10100/log103 = 2/log103
What is log3 12?
4
How do you solve log1 plus log2 plus log3?
log1 + log2 + log3 = log(1*2*3) = log6
What is Log3 3 plus log3 x plus 2 equals 3?
log33+log3x +2=3 log33+log3x=1 log3(3x)=1 3x=3 x=1 Other interpretation: log33+log3(x+2)=3 log3(3(x+2))=3 3(x+2)=27 x+2=9 x=7
What is log3?
1
Log3 81 x log2 8 x log4 2 equals x?
log3 81 × log2 8 × log4 2 = log3 (33) × log2 (23) × log4 (40.5) = 3 × (log3 3) × 3 × (log2 2) × 0.5 × (log4 4) = 3 × 1 × 3 × 1 × 0.5 × 1 = 9 × 0.5 = 4.5
What is 102a if log2 equals a and log3 equals b?
Find 102a if log2=a and log3=b B has no purpose in this question If a=log2, then 102a =102(log2)
What is 13 in base 3?
If you mean: log3(13) then it is 2.334717519
