10log3
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3^(x) = 3^(x) = 50 Take logs base 10 (Calculator) of both sides log3^(x) = log50 xlog3 = log50 x = log50/ log3 (NOT log (50/3)) On the calculator x = 1.6987.../0.47712... x = 3.5608.... 50
The expression x = log3(100) is equivalent to 3x = 100. One way to calculate logs with a base of (b) is: logb(y) = log(y) / log(b). So in this case, you would have log(100) / log(3) = 4.192 [rounded to 3 decimal places]
(9/13) / (10/13) =(9/13) x (13/10) =9/10
15 x 13 = 195A simpler way of breaking this down is:15 x 13 =(10 + 5) x (10 + 3) =(10 x 10) + (10 x 3) + (10 x 5) + (5 x 3) =100 + 30 + 50 + 15 = 195
x+10>13 it wouldn't be x+10-13 ??