If you are looking to factor x^2-6x-40 it'd be (x-10)(x+4). There are two possible solutions. (10,-4)
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This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
In the equation x2 = 6x - 9, all terms must be moved to one side of the equals sign, giving x2 - 6x + 9 = 0. This becomes factorable to (x -3)(x-3).
4(x-1)2(x2+6x+8) and 10(x-1)(x+2)(X2+7x+10)
If we write the problem as 6x-5=x2, then we can write in the form of ax2+bx+c: -x2+6x-5. Then we can use the quadratic equation, x = (-b ± √(b2 - 4ac))/2a, and put in our own values to get the equation x = 3 ± 2. Therefore, x1= 1 and x2=5.
2x+17=6x-23 23+17=6x-2x 40=4x x=40 / 4 therefore x=10