What is the answer to x2 2x-15?

Answer 1

x^2 = 2x -15

x^2 - 2x + 15 = 0 where a = 1, b = -2, and c = 15

x = [-b ± √[b^2 - 4(a)(c)]]/2a

x = [2 ± √[2^2 - 4(1)(15)]]/[2(1)]

x = [2 ± √(4 - 60)]/2

x = [2 ± √(- 56)]/2

x = (2 ± i√56)/2

x = (2 ± 2i√14)/2

x = 1 ± i√14