If x+y = 3 and y times x = 2 then y = 1.
y=x y=6-x Set the two equations equal to each other to yield a solution: x=6-x 2x=6 x=3 x=3 will satisfy both equations, that is plugging in x=3 will give the same value for y y=(3)=3 y=6-(3)=3
x = y+3 x+2y = 9 => x = 9-2y y+3 = 9-2y 2y+y = 9-3 3y = 6 y = 2 and x = 5
y = 3x y = 3*19 = 57
y is directly proportional to x. When y = 15, x = 3 therefore y = 5x When x = 12, then y = 5 x 12 = 60.
x=y
x=4 y=x+3 y=4+3 y=7
3
6
(x, y) = (-3, -3) or (3, 3)
x= z2 - 3
x+y=3 y=3-2x so x+3-2x=3 so x=0 0+y=3 so y=3
x - y = -3 -y = -x - 3 y = x + 3 y-int. = 3 x-int. = -3
If x+y = 3 and y times x = 2 then y = 1.
x=3 y=3.5
0
y = xz where x = 3, z = 10 y = 3 x 10 = 30