If y = 0 then yx - 5 = 0*x - 5 = 0 - 5 = -5
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y = x^5 + x^3 + x^2 + x y' = 5x^(5 - 1) + 3x^(3 - 1) + 2x^(2 -1) + 1x^(1 - 1) (note x^1 = x and x^0 = 1) y' = 5x^4 + 3x^2 + 2x + 1
If you mean: y = -15x+60 then 15x+y = 60 When y = 0 then x = 4 When x = 0 then y = 60 Coordinates of the line are: (4, 0) and (0, 60)
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y = 2x + 5At the y-intercept, x=0.y = 0 + 5y = 5
You state that y + x = -8 The y intercept is where x = 0 so replace that in the formula: y + 0 = -8 So the y intercept is at -8 ... (0, -8) is the point you're looking for.