x-y=0
x=y
so you will use that in the other equation by substituting every y with x
2x+y=0
2x+x=0
3x=0
x=0/3
x=0
then use that in the previous equation by substituting every x with 0
x=y
0=y; y=0
finally x=0 and y=0
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x+xy=8 xy=-x+8 y=-1+8/x
(y-2) (x+4)
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
mid point of xy
xy + x + y + 1 is an expression, not an equation. An expression cannot be solved.