0
∫ 4/x dx
= 4 ∫ 1/x dx
= 4ln(x) + C
This is true for three reasons:
- the derivative of the term ln(x) is equal to 1/x
- 4 is a constant factor of the term, and can be moved out of the integral
- C is an unknown constant, because we're looking at an indefinite integral
You can confirm this by taking the derivative of 4ln(x), which gives you 4/x, the original term.
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Earn +20 ptsQ: What is the antiderivative of 4 divided by x and why?
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Continue Learning about Algebra
What is the integral of x divided by x plus 1?
x/(x+1) = 1 - 1/(x + 1), so the antiderivative (or indefinite integral) is x + ln |x + 1| + C,
What is the antiderivative of logx?
X(logX-1) + C
What is the antiderivative of square root of x?
(2/3)*x^(3/2)
X-2 times x plus 4 divided by x squared - 4?
x-2(x)+4/x^2 -4=x-2x+4/x^2 -4=-x-4+4/x^2
Y equals 4 divided by x squared what formula is this?
Y = 4/x^2
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