Since there are 4 lengths given, the shape could be a quadrilateral. Unfortunately, the lengths of the sides is not enough information to determine the shape of a quadrilateral. As an illustration, consider a square of sides 10 cm. Its area is 100 cm2. But it can be "distorted" into a rhombus with the same sides but the area can be reduced to as close to 0 as you like.
Four linear measures could also mean that it is a 4-dimensional cuboid in hyperspace or some other shape in 2 or 3 dimensions. But since these shapes cannot be determined, it is not possible to find an answer to the question.
Area 51.
Assuming no fractional dimensions, least possible area would be a rectangle measuring 1cm x 9cm. Area increases to a maximum of 25 sq cm when shape is square, ie 5cm x 5cm.
Area = 0.5*base*height Note that the given dimensions would not form a triangle
Without any further information regarding the rectangle, any two numbers that multiply to get 108 will suffice: 1cm x 108cm 2cm x 58cm 3cm x 36cm 4cm x 27cm 6cm x 18cm 9cm x 12cm Plus if the sides are allowed to not be whole numbers, there are many, many more. For example: 10cm x 10.8cm 5cm x 21.6cm
8 because you add all the number and then you divide how many number there are so 6cm + 9cm + 7cm + 10cm = 32cm and 32 divides by 4 equals 8
Area 51.
It's 54
180cm3
To find the area of a rectangle, you multiply the length by the width. In this case, the width is 7cm and the length is 9cm. So, the area would be 7cm x 9cm = 63 square centimeters.
9cm + 5cm + 9cm + 5cm = 28cm
63
18cm 2
83
Dimensions are given out as length by width 14cm by 1cm 13cm by 2cm 12cm by 3cm 11cm by 4cm 10cm by 5cm 9cm by 6cm 8cm by 7cm And the rest is all repeats of the above.
The answer is, you can draw a rectangle with these measurements: 6cm and 9cm 5cm and 10cm 7cm and 8cm
4cm
0cm