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What is the area of a rectangle with length 11cm and width of 9cm?
To find the area (A) of any rectangle, we multiply the length (l) by the width (w). In the case of a rectangle that is 11 cm by 9 cm, we do this:Arectangle = l x w = 11 cm x 9 cm = 99 cm2or 99 square centimeters.
The width of a rectangle is 6 inches less than twice the length find the dimension of the rectangle if its area is 108 square inches?
Let the length of the rectangle be L and the width W, then W = 2L - 6 The area of a rectangle = L x W : 108 = L x (2L - 6) = 2L2 - 6L. Expressing this as a standard quadratic equation gives : 2L2 - 6L - 108 = 0. This can be factored as (2L + 12)(L - 9) = 0. As we are only concerned with positive solutions then the negative solution can be ignored, thus, When L - 9 = 0 then L = 9. As L = 9 then W = 2L - 6 = 18 - 6 = 12. The dimensions of the rectangle are : Width 12 inches, Length 9 inches.
If the area of a rectangle is 18 square inches and the length of the rectangle is twice it's width what is the length and width of the rectangle?
A rectangle with one side that is double the length of the other side can be seen as two squares beside each other, that are half the area of the original rectangle, in this case 18 square inches / 2 = 9 square inches. The side of a square is the square root of the area, in this case the square root of 9 square inches, which is 3 inches. Now think about the rectangle again. What we just counted was the side of a square that made up one half of the rectangle you wanted to calculate the area of. So the shorter side of the rectangle is the same as our square, and the longer side is double the length. So the width of the rectangle is 3 inches, and the length is 2 * 3 inches = 6 inches. Or: Area = length x width (A=lw) Area = 18 (in2) Width = w Length = twice width (2w) 18 = (2w)w 18 = 2w2 9 = w2 3 = w The width is 3 in., the length (2w) is 6 in.
The length of a rectangle is 3 inches more than the width the area of the rectangle is 154 inches Find the width of the rectangle?
Assuming that the area given is actually in squareinches, this can be solved as follows: Call the width inches w. Then, from the problem statement, the length is w + 3 inches. The area of any rectangle is the product of its length and width, so that:w(w+3) = 154; or w2 + 3w - 154 = 0, or (w + 14)(w - 11) = 0. This positive value of w for which this equation is true is 11 inches.
The formula to find the length of a rectangle if the area is given?
A = LW divide by W to both sides A/W = L
What is the area of a rectangle whose length l is 9 m and whose w is 6 m?
The area of rectangle is : 54.0
What the formula for finding the area of a rectangle?
Area of a rectangle: a = l * w
What is the area of a rectangle with length 11cm and width of 9cm?
To find the area (A) of any rectangle, we multiply the length (l) by the width (w). In the case of a rectangle that is 11 cm by 9 cm, we do this:Arectangle = l x w = 11 cm x 9 cm = 99 cm2or 99 square centimeters.
The length of a rectangle is 2cm longer than its width if the perimeter of the rectangle is 40cm find the area?
The rectangle is 99 cm2 in area. Here's how we got it. The rectangle has length (l) and width (w). A length and a length and a width and a width all added up equals 40 cm. And l is 2 cm longer than w, so l = w + 2. If we add w + 2 and w + 2 (the two lengths) and w and w, we get 40 cm. That's 4w + 4 cm = 40 cm. 4w = 36 cm, and w = 9 cm. The width is 9 cm, and the length is 2 cm more or 11 cm. The rectangle is 9 cm by 11 cm, and its area is 9 x 11 cm2, or 99 cm2.
What area of this rectangle?
In order to find the area of a rectangle, you must follow the formula A= l x w where A is area, l is length, and w is width.
What is the area of a rectangle that is 7 ft wide by 9 ft long?
Area of a rectangle equals length times width. A = l x w = 9ft x 7ft = 63ft2
What is the formula for Area a rectangle?
the formula for a rectangle is L x W where L is length and W is width.
What kind of operation do you need to calculate the are of a rectangle?
MULTIPLICATION area for a rectangle is A = L * W * H where, A = area of rectangle L = Length of rectangle W = width of rectangle H = height of rectangle The dimensions of a rectangle (L, W, and H) are interchangeable because they are being multiplied together and hence each side of the rectangle can be arbitrarily assigned to a dimension.
The width of a rectangle measures 4 cm less than the length What is the area of the rectangle if it's perimeter is equal to 100cm?
Let X represent the length, then X-4 represents the width. Perimeter of the rectangle is length plus width multiplied by two. Hence, 2(X + X - 4) = 100; 4X - 8 = 100; 4X = 108; X = 27. The length is 27 mm and the width is 27 - 4 = 23 mm. width = w length = w + 4 perimeter = w + w + w + 4 + w + 4 = 100 4w + 8 = 100 4w = 92 w = 23 width = 23 length = 27 area = 23 x 27 = 621
What is the effect on the perimeter of a rectangle if the dimension are doubled what is the effect on its area?
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
What is the area of the rectangle is its 7yards by 9yards?
to get the area of any square or rectangle you multiply length times width and you would get the answer.So in your case you would multiply 7*9=64yards. *=multiply L*W=A
The width of rectangle is 6 inches less tha twice its length Find the dimension of the rectangle if its area is 108 square inches?
W=12,l=9 ((9*2)-6=12, 12*9=108)
