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What is the area of a rectangle with length 11cm and width of 9cm?
To find the area (A) of any rectangle, we multiply the length (l) by the width (w). In the case of a rectangle that is 11 cm by 9 cm, we do this:Arectangle = l x w = 11 cm x 9 cm = 99 cm2or 99 square centimeters.
The width of a rectangle is 6 inches less than twice the length find the dimension of the rectangle if its area is 108 square inches?
Let the length of the rectangle be L and the width W, then W = 2L - 6 The area of a rectangle = L x W : 108 = L x (2L - 6) = 2L2 - 6L. Expressing this as a standard quadratic equation gives : 2L2 - 6L - 108 = 0. This can be factored as (2L + 12)(L - 9) = 0. As we are only concerned with positive solutions then the negative solution can be ignored, thus, When L - 9 = 0 then L = 9. As L = 9 then W = 2L - 6 = 18 - 6 = 12. The dimensions of the rectangle are : Width 12 inches, Length 9 inches.
If the area of a rectangle is 18 square inches and the length of the rectangle is twice it's width what is the length and width of the rectangle?
A rectangle with one side that is double the length of the other side can be seen as two squares beside each other, that are half the area of the original rectangle, in this case 18 square inches / 2 = 9 square inches. The side of a square is the square root of the area, in this case the square root of 9 square inches, which is 3 inches. Now think about the rectangle again. What we just counted was the side of a square that made up one half of the rectangle you wanted to calculate the area of. So the shorter side of the rectangle is the same as our square, and the longer side is double the length. So the width of the rectangle is 3 inches, and the length is 2 * 3 inches = 6 inches. Or: Area = length x width (A=lw) Area = 18 (in2) Width = w Length = twice width (2w) 18 = (2w)w 18 = 2w2 9 = w2 3 = w The width is 3 in., the length (2w) is 6 in.
The length of a rectangle is 3 inches more than the width the area of the rectangle is 154 inches Find the width of the rectangle?
Assuming that the area given is actually in squareinches, this can be solved as follows: Call the width inches w. Then, from the problem statement, the length is w + 3 inches. The area of any rectangle is the product of its length and width, so that:w(w+3) = 154; or w2 + 3w - 154 = 0, or (w + 14)(w - 11) = 0. This positive value of w for which this equation is true is 11 inches.
The formula to find the length of a rectangle if the area is given?
A = LW divide by W to both sides A/W = L
