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The length of a rectangle is 3 inches more than the width the area of the rectangle is 154 inches Find the width of the rectangle?
Assuming that the area given is actually in squareinches, this can be solved as follows: Call the width inches w. Then, from the problem statement, the length is w + 3 inches. The area of any rectangle is the product of its length and width, so that:
w(w+3) = 154; or w2 + 3w - 154 = 0, or (w + 14)(w - 11) = 0. This positive value of w for which this equation is true is 11 inches.
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The length of a rectangle is 3 inches more than three times the width The perimeter is 78 inches Find the length and width?
Width = 9 inches Length = 30 inches
What is the width of a rectangle with the length of 8 inches greater than its width find the width of the rectangle if its area is 105 square inches?
The dimensions are: length = 15 inches and width = 7 inches Check: 15*7 = 105 square inches
The length of a rectangle is 12 inches. The width of the rectangle is 8 inches. find the perimeter of the rectangle?
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
Find area of a rectangle with a length of 14 inches and a width of 2 inches?
Area=Length*Width A=14 Inches*2 Inches A= 28 square inches or 28 in2
The length of a rectangle is 6 inches more than twice its width If the perimeter of the rectangle is 54 inches find the width of the rectangle?
Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)
What is The length of a rectangle is 3 inches less than twice the width. If the perimeter of the rectangle is 18 inches find the width of the rectangle?
Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter
The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
The length of a rectangle is 8 inches greater than its width Find the width of the rectangle if its area is 105 square inches?
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The length of a rectangle is 3 inches more than three times the width The perimeter is 78 inches Find the length and width?
Width = 9 inches Length = 30 inches
What is the width of a rectangle with the length of 8 inches greater than its width find the width of the rectangle if its area is 105 square inches?
The dimensions are: length = 15 inches and width = 7 inches Check: 15*7 = 105 square inches
The length of a rectangle is 12 inches. The width of the rectangle is 8 inches. find the perimeter of the rectangle?
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
The length of a rectangle is 2 inches greater than the width the area is 80 inches squared find the length of the rectangle?
10 in. A+LS
Find the area of a rectangle where 1 5 inches and w 4 inches?
To find the area of a rectangle, multiply the length times the width.
How do you find the area of a rectangle in square cubic inches?
To find the area of a rectangle, multiply the length times the width. The result will be in square inches.
Find area of a rectangle with a length of 14 inches and a width of 2 inches?
Area=Length*Width A=14 Inches*2 Inches A= 28 square inches or 28 in2
The Area of a rectangle is 28 inches. Find the Width if its length is 3 inches greater than its width.?
Length 7 inches and width 4 inches because 7*4 = 28 square inches
The length of a rectangle is 6 inches more than twice its width If the perimeter of the rectangle is 54 inches find the width of the rectangle?
Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)
