15x9 = 135 squared feet
52 ft
The area of a 95 ft by 25 ft rectangle is 95*25 = 2375 square feet and the perimeter is 2*(95 + 25) = 240 feet
Area of square = 4 x 4 = 16 sq ft; area of rectangle = 3 x 2 = 6 sq ft. Area of the square is two-and-two-thirds that of the rectangle.
52 (13•4)
The area of rectangle is : 120.0
The area of a rectangle is the product of its length multiplied by its width.Area 25 ft x 15 ft = 375 square feet.
is it used in squre units
15 feet squared
135 ft2
15 ft
Area of a rectangle = (length) times (width) = 10-ft x 12-ft = 120 square feet
12*10 = 120 square feet
Area of a rectangle = (length) x (width) = 10-ft x 5-ft = 50 square feet
The area cannot be 15 feet since that is a measure of length, not area. In any case, information about the area cannot determine the perimeter; it can only put a lower limit on it. The perimeter can be anyhting from 15.49193 ft upwards. Consider the following rectangles, all with area = 15 square feet: a sqrt(15)*sqrt(15) rectangle will have a perimeter of 4*sqrt(15) = 15.49193 ft (approx). 1ft*15ft rectangle will have a perimeter of 32 feet 0.1ft*150ft rectangle: perimeter = 300.2 feet 0.01ft*1500ft rectangle: perimeter = 3000.02 ft 0.001ft*15000ft rectangle: perimeter = 30000.002 ft by now you should see that there is no upper limit to the perimeter.
There need not be any as an area can have any shape; for example 4000 sq ft can be a rectangle with side lengths 1 ft and 4000 ft - as this rectangle has a width of 1 ft a 10 ft by 10 ft area cannot be extracted from it. However, if you are asking how many sections with the same area as a square of sides 10 ft can be made in an area of 4000 sq ft, then: 4000 sq ft ÷ (10 ft × 10 ft) = 4000 sq ft ÷ 100 sq ft = 40.
The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.