answersLogoWhite

0

formula for area of a rectangle is length times width

in this equation 15ft is your length and 10ft is your width

so.... 15 x 10 = 150

your final answer is 150ft squared (150 feet squared)

User Avatar

Wiki User

12y ago

What else can I help you with?

Related Questions

What is the area of a rectangle with the width of 12 ft in the length of 10 ft?

The area of rectangle is : 120.0


What is the area of a rectangle 25 ft by 15 ft?

The area of a rectangle is the product of its length multiplied by its width.Area 25 ft x 15 ft = 375 square feet.


What is the area of a rectangle 5 ft x 3 ft?

15 feet squared


What is the area of a rectangle with a length of 15 ft and witdth of 9 ft?

135 ft2


How do you find area of rectangle 25 ft by 15 ft?

is it used in squre units


What is the length of a rectangle that has an area of 120ft and a width of 8ft?

15 ft


What is the area of a rectangle with a width of 12 feet sand a length of 10 feet?

Area of a rectangle = (length) times (width) = 10-ft x 12-ft = 120 square feet


What is the area of a rectangle with the 12 ft wide and 10 ft long?

12*10 = 120 square feet


What is the area of a rectangle if the length is 10ft and the width is 5ft?

Area of a rectangle = (length) x (width) = 10-ft x 5-ft = 50 square feet


How many 10x10 areas are in 4000 square feet?

There need not be any as an area can have any shape; for example 4000 sq ft can be a rectangle with side lengths 1 ft and 4000 ft - as this rectangle has a width of 1 ft a 10 ft by 10 ft area cannot be extracted from it. However, if you are asking how many sections with the same area as a square of sides 10 ft can be made in an area of 4000 sq ft, then: 4000 sq ft ÷ (10 ft × 10 ft) = 4000 sq ft ÷ 100 sq ft = 40.


What is the perimeter of a rectangle if ti's area is 15ft?

The area cannot be 15 feet since that is a measure of length, not area. In any case, information about the area cannot determine the perimeter; it can only put a lower limit on it. The perimeter can be anyhting from 15.49193 ft upwards. Consider the following rectangles, all with area = 15 square feet: a sqrt(15)*sqrt(15) rectangle will have a perimeter of 4*sqrt(15) = 15.49193 ft (approx). 1ft*15ft rectangle will have a perimeter of 32 feet 0.1ft*150ft rectangle: perimeter = 300.2 feet 0.01ft*1500ft rectangle: perimeter = 3000.02 ft 0.001ft*15000ft rectangle: perimeter = 30000.002 ft by now you should see that there is no upper limit to the perimeter.


Area of a rhombus with diagonals of 8 ft and 10 ft?

The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.