A = 540 units squared.
The rectangle has a length of 12 cm and a width of 3 cm.
Length is 11 and width is 7 and so 11 times 7 = 77 square cm
L = 5W 2L + 2W = 72 ==> L + W = 36 Substitute L = 5W: 5W + W = 6W = 36. ==> W = 6, and L = 30. Area = 180
perimeter = 2*width + 2*length 36= 2*8 +2*length2*length=36-162*length=20length = 10 cm
243 = 27 x 9 so perimeter is 2 x 36 ie 72.
It is: 12 units in length
Area of the rectangle = 36 =Length * Width Assume Width= a Hence Length = 4*a =4a Area = a*4a =36 Therefore, a*a =9 Hence a =3 =Width
36
if the length is 36 on a rectangle then what is the width of the rectangle
It would have an area of 36 sq. inches. The formula for finding the area of a rectangle is length times width. 6*6=36.
9 inches
Length = 9 Width = 9 Your rectangle is a square.
1944 in. Length x Width = Area
36 cm2 Area of a rectangle is length times width, so you would multipy 12cm by 3 cm to get 36 sq. (squared) cm.
Rectangle area = L x W1.260 in2 = 36 in x W in (divide both sides by 36 in)35 in = W
Length is 12 width is 3? if that's what you meant.
Perimeter is 36 mArea is 72 square m