Length = 9
Width = 9
Your rectangle is a square.
It is a 3 x 15 rectangle !
The area is 72 The dimensions would be 6x12 6 * 2 + 12 * 2 = 36
A square can't have a perimeter of 36 and an area of 45. If a square's perimeter is 36,then its area is 81. If a square's area is 45, then its perimeter is about 26.83 . (rounded)A figure whose perimeter is 36 and whose area is 45 is not a square. It's a rectanglethat measures (3 by 15).
It is: 12 units in length
Length + Width = 9, becomes 36, eg 8 + 1 becomes 32 + 4 or 5 + 4 becomes 20 + 16 New perimeter is 2 x 36 = 72 cm
It is a 3 x 15 rectangle !
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
The area is 72 The dimensions would be 6x12 6 * 2 + 12 * 2 = 36
Yes if its dimensions were 3 cm and 12 cm.
Draw the table and calculate the area of the triangle the area of a square is 36
Perimeter is 36 mArea is 72 square m
A square can't have a perimeter of 36 and an area of 45. If a square's perimeter is 36,then its area is 81. If a square's area is 45, then its perimeter is about 26.83 . (rounded)A figure whose perimeter is 36 and whose area is 45 is not a square. It's a rectanglethat measures (3 by 15).
The perimeter doesn't tell you the area. There are an infinite number of differentareas that it could have.-- If it's a circle with a perimeter of 36, then the area is 103.1324. (rounded)-- If it's a square with a perimeter of 36, then the area is 81 .-- If it's a rectangle with a perimeter of 36, then the area can be any numberthat's more than zero and less than 81 .
It is: 12 units in length
The shape that has a perimeter of 26 cm and an area of 36 cm² is a rectangle. To find the dimensions of the rectangle, we need to set up equations based on the given information. Let the length be L and the width be W. The perimeter formula for a rectangle is P = 2(L + W) and the area formula is A = L * W. By solving the system of equations P = 26, A = 36, we can find that the dimensions of the rectangle are length = 9 cm and width = 4 cm.
Length + Width = 9, becomes 36, eg 8 + 1 becomes 32 + 4 or 5 + 4 becomes 20 + 16 New perimeter is 2 x 36 = 72 cm
81 square feet.